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प्रश्न
Solve the following equation:
उत्तर
\[\Rightarrow 2 \sin\left( \frac{6x}{2} \right) \cos \left( \frac{4x}{2} \right) = \sin3x\]
\[ \Rightarrow 2 \sin3x \cos2x = \sin3x\]
\[ \Rightarrow 2 \sin3x \cos2x - \sin3x = 0\]
\[ \Rightarrow \sin3x (2 \cos2x - 1) = 0\]
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