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प्रश्न
`int ("e"^(2x) + "e"^(-2x))/("e"^x) "d"x`
उत्तर
`int ("e"^(2x) + "e"^(-2x))/("e"^x) "d"x = int("e"^x + "e"^(-3x)) "d"x`
= `"e"^x - ("e"^(-3x))/3 + "c"`
= `"e"^x - 1/(3"e"^(3x)) + "c"`
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