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प्रश्न
\[\ \int\ x \left( 1 - x \right)^{23} dx\]
योग
उत्तर
\[\int\ x \left( 1 - x \right)^{23} dx\]
\[\text{Let 1 - x }= t \]
\[ \Rightarrow x = 1 - t\]
\[ \Rightarrow 1 = - \frac{dt}{dx}\]
\[ \Rightarrow dx = - dt\]
\[Now, \int\ x \left( 1 - x \right)^{23} dx\]
\[ = - \int\left( 1 - t \right) \cdot t^{23} dt\]
\[ = - \int\left( t^{23} - t^{24} \right)dt\]
\[ = \int\left( t^{24} - t^{23} \right) dt\]
\[ = \frac{t^{25}}{25} - \frac{t^{24}}{24} + C\]
\[ = \frac{24 t^{25} - 25 t^{24}}{600} + C\]
\[ = \frac{t^{24}}{600}\left[ 24t - 25 \right] + C\]
\[ = \frac{\left( 1 - x \right)^{24}}{600} \left[ 24\left( 1 - x \right) - 25 \right] + C\]
\[ = \frac{- 1}{600} \left( 1 - x \right)^{24} \left( 1 + 24x \right) + C\]
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