मराठी

∫ √ 3 − X 2 D X - Mathematics

Advertisements
Advertisements

प्रश्न

\[\int\sqrt{3 - x^2} \text{ dx}\]
बेरीज

उत्तर

\[\text{ Let I } = \int\sqrt{3 - x^2}\text{ dx}\]
\[ = \int\sqrt{\left( \sqrt{3} \right)^2 - x^2}\text{ dx} \]
\[ = \frac{x}{2}\sqrt{\left( \sqrt{3} \right)^2 - x^2} + \frac{\left( \sqrt{3} \right)^2}{2} \sin^{- 1} \left( \frac{x}{\sqrt{3}} \right) + C\]
\[ = \frac{x}{2} \sqrt{3 - x^2} + \frac{3}{2} \sin^{- 1} \left( \frac{x}{\sqrt{3}} \right) + C\]

shaalaa.com
  या प्रश्नात किंवा उत्तरात काही त्रुटी आहे का?
पाठ 19: Indefinite Integrals - Exercise 19.28 [पृष्ठ १५५]

APPEARS IN

आरडी शर्मा Mathematics [English] Class 12
पाठ 19 Indefinite Integrals
Exercise 19.28 | Q 16 | पृष्ठ १५५

व्हिडिओ ट्यूटोरियलVIEW ALL [1]

संबंधित प्रश्‍न

\[\int\frac{\sin^3 x - \cos^3 x}{\sin^2 x \cos^2 x} dx\]

\[\int\frac{1}{\sqrt{2x + 3} + \sqrt{2x - 3}} dx\]

\[\int \sin^2\text{ b x dx}\]

\[\int \cos^2 \text{nx dx}\]

\[\int\frac{\text{sin} \left( x - a \right)}{\text{sin}\left( x - b \right)} dx\]

\[\int\frac{- \sin x + 2 \cos x}{2 \sin x + \cos x} dx\]

\[\int\frac{\sin 2x}{a^2 + b^2 \sin^2 x} dx\]

` ∫  tan 2x tan 3x  tan 5x    dx  `

\[\int\frac{\sin 2x}{\sin \left( x - \frac{\pi}{6} \right) \sin \left( x + \frac{\pi}{6} \right)} dx\]

\[\int\frac{x}{\sqrt{x^2 + a^2} + \sqrt{x^2 - a^2}} dx\]

\[\int \sin^3 x \cos^6 x \text{ dx }\]

\[\int\frac{1}{a^2 x^2 + b^2} dx\]

\[\int\frac{x}{3 x^4 - 18 x^2 + 11} dx\]

\[\int\frac{x}{\sqrt{x^2 + 6x + 10}} \text{ dx }\]

\[\int\frac{2}{2 + \sin 2x}\text{ dx }\]

\[\int\frac{1}{13 + 3 \cos x + 4 \sin x} dx\]

\[\int\frac{8 \cot x + 1}{3 \cot x + 2} \text{  dx }\]

\[\int x^2 \text{ cos x dx }\]

\[\int\frac{\text{ log }\left( x + 2 \right)}{\left( x + 2 \right)^2}  \text{ dx }\]

\[\int \log_{10} x\ dx\]

\[\int e^x \frac{\left( 1 - x \right)^2}{\left( 1 + x^2 \right)^2} \text{ dx }\]

\[\int\sqrt{2x - x^2} \text{ dx}\]

\[\int\frac{x^2 + 1}{\left( 2x + 1 \right) \left( x^2 - 1 \right)} dx\]

\[\int\frac{4 x^4 + 3}{\left( x^2 + 2 \right) \left( x^2 + 3 \right) \left( x^2 + 4 \right)} dx\]

\[\int\frac{x^4}{\left( x - 1 \right) \left( x^2 + 1 \right)} dx\]

\[\int\frac{x + 1}{\left( x - 1 \right) \sqrt{x + 2}} \text{ dx }\]

\[\int\frac{1}{\left( x + 1 \right) \sqrt{x^2 + x + 1}} \text{ dx }\]

\[\int\frac{x + 2}{\left( x + 1 \right)^3} \text{ dx }\]


\[\int\frac{\sin x + \cos x}{\sqrt{\sin 2x}} \text{ dx}\]

\[\int\frac{1}{\text{ sin} \left( x - a \right) \text{ sin } \left( x - b \right)} \text{ dx }\]

\[\int\frac{1}{\text{ cos }\left( x - a \right) \text{ cos }\left( x - b \right)} \text{ dx }\]

\[\int\frac{\sin x}{\sqrt{1 + \sin x}} dx\]

\[\int \cos^5 x\ dx\]

\[\int\frac{1}{1 + 2 \cos x} \text{ dx }\]

\[\int\sqrt{a^2 - x^2}\text{  dx }\]

\[\int\left( 2x + 3 \right) \sqrt{4 x^2 + 5x + 6} \text{ dx}\]

\[\int x \sec^2 2x\ dx\]

\[\int e^x \frac{\left( 1 - x \right)^2}{\left( 1 + x^2 \right)^2} \text{ dx }\]

Evaluate : \[\int\frac{\cos 2x + 2 \sin^2 x}{\cos^2 x}dx\] .


\[\int\frac{x^2}{x^2 + 7x + 10}\text{ dx }\]

Share
Notifications

Englishहिंदीमराठी


      Forgot password?
Use app×