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प्रश्न

\[\int\limits_0^1 \cos^{- 1} x dx\]

योग

उत्तर

\[\int_0^1 \cos^{- 1} x d x\]

\[ = \int_0^1 \left( \cos^{- 1} x \times 1 \right) d x\]

\[ = \left[ \cos^{- 1} x x \right]_0^1 - \int_0^1 \frac{- x}{\sqrt{1 - x^2}}dx\]

\[ = \left[ x \cos^{- 1} x \right]_0^1 - \frac{2}{2} \left[ \sqrt{1 - x^2} \right]_0^1 \]

\[ = 0 + 1\]

\[ = 1\]

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Definite Integrals
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अध्याय 20: Definite Integrals - Revision Exercise [पृष्ठ १२१]

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आरडी शर्मा Mathematics [English] Class 12
अध्याय 20 Definite Integrals
Revision Exercise | Q 4 | पृष्ठ १२१

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