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प्रश्न
उत्तर
\[\int_0^\frac{\pi}{2} \sqrt{1 - \cos2x}\ dx\]
\[ = \int_0^\frac{\pi}{2}\sqrt{2 \sin^2 x}\ dx\]
\[ = \int_0^\frac{\pi}{2} \sqrt{2} \sin x\ dx\]
\[ = - \sqrt{2} \left[ \cos x \right]_0^\frac{\pi}{2} \]
\[ = - \left( 0 - \sqrt{2} \right)\]
\[ = \sqrt{2}\]
\[\]
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