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प्रश्न
विकल्प
- \[\frac{\pi}{12}\]
- \[\frac{\pi}{6}\]
- \[\frac{\pi}{4}\]
- \[\frac{\pi}{3}\]
\[\frac{\pi}{2}\]
\[\frac{2\pi}{3}\]
उत्तर
Explanation:
Let I = `int_1^sqrt(3) dx/(1 + x^2)`
= `[tan^-1 x]_1^sqrt(3)`
= `tan^-1 sqrt(3) - tan^-1 1`
= `π/3 - π/4`
= `(4π - 3π)/12`
= `π/12`
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