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प्रश्न
` ∫ tan^3 x sec^2 x dx `
योग
उत्तर
` ∫ tan^3 x sec^2 x dx `
Let tan x = t
⇒ sec2 x dx = dt
Now ,` ∫ tan^3 x sec^2 x dx `
`= ∫ t^3.dt `
\[= \frac{t^4}{4} + C\]
`= ∫ t^3.dt `
\[= \frac{t^4}{4} + C\]
\[ = \frac{\tan^4 x}{4} + C\]
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