मराठी

\[\Int\Left( 3x\Sqrt{X} + 4\Sqrt{X} + 5 \Right)Dx\] - Mathematics

Advertisements
Advertisements

प्रश्न

\[\int\left( 3x\sqrt{x} + 4\sqrt{x} + 5 \right)dx\]
बेरीज

उत्तर

\[\int\left( 3x\sqrt{x} + 4\sqrt{x} + 5 \right)dx\]
\[ = \int\left( 3 x^1 \cdot x^\frac{1}{2} + 4 x^\frac{1}{2} + 5 \right)dx\]
\[ = 3\int x^\frac{3}{2} dx + 4\int x^\frac{1}{2} dx + 5 ∫dx\]
\[ = 3\left[ \frac{x^\frac{3}{2} + 1}{\frac{3}{2} + 1} \right] + 4\left[ \frac{x^\frac{1}{2} + 1}{\frac{1}{2} + 1} \right] + 5x + C\]
\[ = 3 \times \frac{2}{5} x^\frac{5}{2} + 4 \times \frac{2}{3} x^\frac{3}{2} + 5x + C\]
\[ = \frac{6}{5} x^\frac{5}{2} + \frac{8}{3} x^\frac{3}{2} + 5x + C\]

shaalaa.com
  या प्रश्नात किंवा उत्तरात काही त्रुटी आहे का?
पाठ 19: Indefinite Integrals - Exercise 19.02 [पृष्ठ १४]

APPEARS IN

आरडी शर्मा Mathematics [English] Class 12
पाठ 19 Indefinite Integrals
Exercise 19.02 | Q 1 | पृष्ठ १४

व्हिडिओ ट्यूटोरियलVIEW ALL [1]

संबंधित प्रश्‍न

\[\int\left( 2 - 3x \right) \left( 3 + 2x \right) \left( 1 - 2x \right) dx\]

 
\[\int\frac{\cos x}{1 - \cos x} \text{dx }or \int\frac{\cot x}{\text{cosec         } {x }- \cot x} dx\]

\[\int\frac{1}{1 - \sin\frac{x}{2}} dx\]

` ∫    cos  mx  cos  nx  dx `

 


\[\int\sqrt{\frac{1 + \cos 2x}{1 - \cos 2x}} dx\]

` ∫  {sin 2x} /{a cos^2  x  + b sin^2  x }  ` dx 


` ∫  tan 2x tan 3x  tan 5x    dx  `

\[\int\left( \frac{x + 1}{x} \right) \left( x + \log x \right)^2 dx\]

\[\int\frac{x + \sqrt{x + 1}}{x + 2} dx\]

\[\int\frac{1}{\sqrt{1 + 4 x^2}} dx\]

 


\[\int\frac{x^2 - 1}{x^2 + 4} dx\]

\[\int\frac{1}{1 + x - x^2}  \text{ dx }\]

\[\int\frac{x}{x^4 + 2 x^2 + 3} dx\]

\[\int\frac{1}{\sqrt{7 - 3x - 2 x^2}} dx\]

\[\int\frac{1}{\sqrt{5 x^2 - 2x}} dx\]

\[\int\frac{1}{x\sqrt{4 - 9 \left( \log x \right)^2}} dx\]

\[\int\frac{\sin 2x}{\sqrt{\sin^4 x + 4 \sin^2 x - 2}} dx\]

\[\int\frac{x^2 + x + 1}{x^2 - x + 1} \text{ dx }\]

\[\int\frac{6x - 5}{\sqrt{3 x^2 - 5x + 1}} \text{ dx }\]

\[\int\frac{1}{3 + 2 \cos^2 x} \text{ dx }\]

\[\int\frac{1}{3 + 4 \cot x} dx\]

\[\int x \sin x \cos 2x\ dx\]

\[\int \sin^{- 1} \sqrt{\frac{x}{a + x}} \text{ dx }\]

\[\int e^x \left( \tan x - \log \cos x \right) dx\]

\[\int e^x \left( \frac{x - 1}{2 x^2} \right) dx\]

\[\int\frac{e^x}{x}\left\{ \text{ x }\left( \log x \right)^2 + 2 \log x \right\} dx\]

\[\int x\sqrt{x^2 + x} \text{  dx }\]

\[\int(2x + 5)\sqrt{10 - 4x - 3 x^2}dx\]

\[\int\frac{x^3 - 1}{x^3 + x} dx\]

\[\int\frac{1}{x \left( x^4 - 1 \right)} dx\]

\[\int\frac{x}{\left( x^2 + 2x + 2 \right) \sqrt{x + 1}} \text{ dx}\]

\[\int\frac{1}{7 + 5 \cos x} dx =\]

\[\int\frac{\sin 2x}{a^2 + b^2 \sin^2 x}\]

\[\int\frac{1}{4 \sin^2 x + 4 \sin x \cos x + 5 \cos^2 x} \text{ dx }\]


\[\int\frac{1}{\sin^2 x + \sin 2x} \text{ dx }\]

\[\int\frac{1 + x^2}{\sqrt{1 - x^2}} \text{ dx }\]

\[\int \tan^{- 1} \sqrt{\frac{1 - x}{1 + x}} \text{ dx }\]

\[\int\frac{\cot x + \cot^3 x}{1 + \cot^3 x} \text{ dx}\]

Find : \[\int\frac{dx}{\sqrt{3 - 2x - x^2}}\] .


Share
Notifications

Englishहिंदीमराठी


      Forgot password?
Use app×