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Question
Solution
\[\int_0^1 \frac{1}{1 + x^2} d x\]
\[ = \left[ \tan^{- 1} x \right]_0^1 \]
\[ = \tan^{- 1} 1 - \tan^{- 1} 0\]
\[ = \frac{\pi}{4} - 0\]
\[ = \frac{\pi}{4}\]
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