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प्रश्न

\[\int\frac{1 - \cos x}{1 + \cos x} dx\]
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उत्तर

\[\int\left( \frac{1 - \cos x}{1 + \cos x} \right) dx\]

`= ∫ ( {2 sin ^2  x/2 }/ {2 cos ^2  x/2})` dx   ` [ 1 - cos x = 2   sin ^2  x/2  &  1 + cos x  = 2 cos ^2   x/2]`

\[ = \int \tan^2 \frac{x}{2} dx\]

\[ = \int\left( \sec^2  \frac{x}{2} - 1 \right) dx\]

\[ = \frac{\tan \frac{x}{2}}{\frac{1}{2}} - x + C\]

\[ = 2 \tan \frac{x}{2} - x + C\]

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अध्याय 19: Indefinite Integrals - Exercise 19.03 [पृष्ठ २३]

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आरडी शर्मा Mathematics [English] Class 12
अध्याय 19 Indefinite Integrals
Exercise 19.03 | Q 11 | पृष्ठ २३

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