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प्रश्न
\[\int \left( \sqrt{x} - \frac{1}{\sqrt{x}} \right)^2 dx\]
योग
उत्तर
\[\int \left( \sqrt{x} - \frac{1}{\sqrt{x}} \right)^2 dx\]
\[ = \int\left( x + \frac{1}{x} - 2 \right)dx\]
` = ∫ x dx + ∫ dx/x - 2\ ∫ x dx`
`= x^2 / 2 + In | x| -2 x +C`
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