English

Evaluate: dx∫cos−1⁡(sin⁡x)dx - Mathematics

Advertisements
Advertisements

Question

Evaluate:

\[\int \cos^{-1} \left(\sin x \right) \text{dx}\]

Sum

Solution

\[\int \cos^{-1} \left(\sin x \right)\text{ dx }\]

\[= \int \cos^{-1} \left( \cos\left( \frac{\pi}{2} - x \right) \right) \text{ dx }\]

\[ = \int \left(\frac{\pi}{2} - x \right) dx\]

\[ = \frac{\pi}{2}x - \frac{1}{2} x^2 + c\]

\[\text{Hence,}\int \cos^{-1} \left(\sin x \right)\text{ dx } = \frac{\pi}{2}x - \frac{1}{2} x^2 + c\]

shaalaa.com
  Is there an error in this question or solution?
Chapter 19: Indefinite Integrals - Very Short Answers [Page 198]

APPEARS IN

RD Sharma Mathematics [English] Class 12
Chapter 19 Indefinite Integrals
Very Short Answers | Q 60 | Page 198

RELATED QUESTIONS

`∫   x    \sqrt{x + 2}     dx ` 

\[\int\frac{x}{\sqrt{x + 4}} dx\]

\[\int\sqrt{\frac{1 - \cos x}{1 + \cos x}} dx\]

Evaluate the following integrals: 

`int "sec x"/"sec 2x" "dx"`

\[\int\frac{\cos 2x}{\left( \cos x + \sin x \right)^2} dx\]

\[\int\frac{1 + \tan x}{1 - \tan x} dx\]

` ∫ {cot x}/ { log sin x} dx `

\[\int\frac{e^{2x}}{e^{2x} - 2} dx\]

\[\int\frac{10 x^9 + {10}^x \log_e 10}{{10}^x + x^{10}} dx\]

` ∫  {1+tan}/{ x + log  sec  x   dx} `

\[\int\frac{e^{x - 1} + x^{e - 1}}{e^x + x^e} dx\]

\[\int\frac{1}{\sin x \cos^2 x} dx\]

\[\int\frac{1}{\cos 3x - \cos x} dx\]

 ` ∫       cot^3   x  "cosec"^2   x   dx `


\[\int\frac{\left\{ e^{\sin^{- 1} }x \right\}^2}{\sqrt{1 - x^2}} dx\]


\[\int\frac{1}{\sqrt{1 - x^2} \left( \sin^{- 1} x \right)^2} dx\]


\[\int\frac{\cot x}{\sqrt{\sin x}} dx\]


`  ∫    {1} / {cos x  + "cosec x" } dx  `

\[\int\frac{x^3 - 3x}{x^4 + 2 x^2 - 4}dx\]

Evaluate the following integrals: 

\[\int\frac{x + 2}{\sqrt{x^2 + 2x + 3}} \text{ dx }\]

\[\int\frac{1}{\sin x + \cos x} \text{ dx }\]

\[\int\frac{1}{5 - 4 \cos x} \text{ dx }\]

\[\int\left( x - 3 \right)\sqrt{x^2 + 3x - 18} \text{  dx }\]

\[\int\frac{a x^2 + bx + c}{\left( x - a \right) \left( x - b \right) \left( x - c \right)} dx,\text{ where a, b, c are distinct}\]

Evaluate the following integral:

\[\int\frac{x^2}{\left( x^2 + 4 \right)\left( x^2 + 9 \right)}dx\]

Evaluate the following integral:

\[\int\frac{x^2 + 1}{\left( x^2 + 4 \right)\left( x^2 + 25 \right)}dx\]

\[\int\frac{2x + 1}{\left( x + 2 \right) \left( x - 3 \right)^2} dx\]

\[\int\frac{\cos x}{\left( 1 - \sin x \right) \left( 2 - \sin x \right)} dx\]

Evaluate the following integrals:

\[\int\frac{x^2}{(x - 1) ( x^2 + 1)}dx\]

Evaluate the following integral:

\[\int\frac{x^2}{x^4 - x^2 - 12}dx\]

 


Evaluate the following integral:

\[\int\frac{x^2}{x^4 + x^2 - 2}dx\]

\[\int\frac{( x^2 + 1) ( x^2 + 4)}{( x^2 + 3) ( x^2 - 5)} dx\]

\[\int\frac{x^2 + 1}{x^4 - x^2 + 1} \text{ dx }\]

Evaluate the following integral:

\[\int\frac{1}{\sin^4 x + \sin^2 x \cos^2 x + \cos^4 x}dx\]

Write a value of

\[\int\frac{\left( \log x \right)^n}{x} \text{ dx }\]

Evaluate:\[\int\frac{x^2}{1 + x^3} \text{ dx }\] .


Evaluate:

\[\int\frac{x^2 + 4x}{x^3 + 6 x^2 + 5} \text{ dx }\]

Evaluate:\[\int\frac{\sec^2 \sqrt{x}}{\sqrt{x}} \text{ dx }\]

 


Evaluate:\[\int\frac{\sin \sqrt{x}}{\sqrt{x}} \text{ dx }\]


Evaluate:\[\int\frac{\cos \sqrt{x}}{\sqrt{x}} \text{ dx }\]


Evaluate:\[\int \sec^2 \left( 7 - 4x \right) \text{ dx }\]


Evaluate:\[\int\frac{\log x}{x} \text{ dx }\]


Evaluate:  \[\int 2^x  \text{ dx }\]


Evaluate: \[\int\frac{1}{\sqrt{1 - x^2}} \text{ dx }\]


Evaluate: \[\int\left( 1 - x \right)\sqrt{x}\text{  dx }\]


Evaluate: 

\[\int\frac{1}{\sin^2 x \cos^2 x}dx\]

Evaluate: `int_  (x + sin x)/(1 + cos x )  dx`


Evaluate the following:

`int ("d"x)/sqrt(16 - 9x^2)`


Evaluate the following:

`int_1^2 ("d"x)/sqrt((x - 1)(2 - x))`


Share
Notifications

Englishहिंदीमराठी


      Forgot password?
Use app×