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प्रश्न
\[\int\frac{\cos\sqrt{x}}{\sqrt{x}} dx\]
बेरीज
उत्तर
\[\int\frac{\cos \sqrt{x}}{\sqrt{x}}dx\]
\[\text{Let} \sqrt{x} = t\]
\[ \Rightarrow \frac{1}{2\sqrt{x}} = \frac{dt}{dx}\]
\[ \Rightarrow \frac{dx}{\sqrt{x}} = 2 dt\]
\[Now, \int\frac{\cos \sqrt{x}}{\sqrt{x}}dx\]
\[ = 2\int\text{cos t dt} \]
\[ = 2 \sin t + C\]
\[ = 2 \sin \sqrt{x} + C\]
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