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प्रश्न
∴\[\int e^{2x} \left( - \sin x + 2 \cos x \right) dx\]
बेरीज
उत्तर
\[\text{ Let I } = \int e^{2x} \left( - \sin x + 2\cos x \right)dx\]
\[\text{ Put e}^{2x} \cos x = t\]
\[\text{ Diff both sides w . r . t x }\]
\[\left[ 2 e^{2x} \cos x + e^{2x} \times \left( - \sin x \right) \right]dx = dt\]
` ∴ \text{ I } = \int dt `
\[ = t + C\]
\[ = e^{2x} \cos x + C\]
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