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प्रश्न
विकल्प
1
2
− 1
− 2
उत्तर
2
\[\int_{- \frac{\pi}{2}}^\frac{\pi}{2} \sin\left| x \right| d x\]
\[ = - \int_{- \frac{\pi}{2}}^0 \sin x\ dx + \int_0^\frac{\pi}{2} \sin x\ dx\]
\[ = - \left[ - \cos x \right]_{- \frac{\pi}{2}}^0 + \left[ - \cos x \right]_0^\frac{\pi}{2} \]
\[ = 1 - 0 - 0 + 1\]
\[ = 2\]
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