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प्रश्न
`int logx/x "d"x`
उत्तर
Put log x = t
∴ `1/x "d"x` = dt
∴ `int logx/x "d"x = int "t" "dt"`
= `"t"^2/2 + "c"`
`((log x)^2)/2 + "c"`
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