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Tamil Nadu Board of Secondary EducationHSC Science Class 11

Samacheer Kalvi solutions for Mathematics - Volume 1 and 2 [English] Class 11 TN Board chapter 9 - Differential Calculus - Limits and Continuity [Latest edition]

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Samacheer Kalvi solutions for Mathematics - Volume 1 and 2 [English] Class 11 TN Board chapter 9 - Differential Calculus - Limits and Continuity - Shaalaa.com
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Solutions for Chapter 9: Differential Calculus - Limits and Continuity

Below listed, you can find solutions for Chapter 9 of Tamil Nadu Board of Secondary Education Samacheer Kalvi for Mathematics - Volume 1 and 2 [English] Class 11 TN Board.


Exercise 9.1Exercise 9.2Exercise 9.3Exercise 9.4Exercise 9.5Exercise 9.6
Exercise 9.1 [Pages 95 - 98]

Samacheer Kalvi solutions for Mathematics - Volume 1 and 2 [English] Class 11 TN Board 9 Differential Calculus - Limits and Continuity Exercise 9.1 [Pages 95 - 98]

Exercise 9.1 | Q 1 | Page 95

In problems 1 – 6, using the table estimate the value of the limit.

`lim_(x -> 2) (x - 2)/(x^2 - x - 2)`

x 1.9 1.99 1.999 2.001 2.01 2.1
f(x) 0.344820 0.33444 0.33344 0.333222 0.33222 0.332258
Exercise 9.1 | Q 2 | Page 95

In problems 1 – 6, using the table estimate the value of the limit
`lim_(x -> 2) (x - 2)/(x^2 - 4)`

x 1.9 1.99 1.999 2.001 2.01 2.1
f(x) 0.25641 0.25062 0.250062 0.24993 0.24937 0.24390
Exercise 9.1 | Q 3 | Page 95

In problems 1 – 6, using the table estimate the value of the limit
`lim_(x -> 0) (sqrt(x + 3) - sqrt(3))/x`

x – 0.1  – 0.01 – 0.001 0.001 0.01 0.1
f(x) 0.2911 0.2891 0.2886 0.2886 0.2885 0.28631
Exercise 9.1 | Q 4 | Page 95

In problems 1 – 6, using the table estimate the value of the limit
`lim_(x -> - 3) (sqrt(1 - x) - 2)/(x + 3)`

x – 3.1  – 3.01 – 3.00 – 2.999 – 2.99 – 2.9
f(x) – 0.24845 – 0.24984 – 0.24998 – 0.25001 – 0.25015 – 0.25158
Exercise 9.1 | Q 5 | Page 95

In problems 1 – 6, using the table estimate the value of the limit
`lim_(x -> 0) sin x/x`

x – 0.1  – 0.01 – 0.001 0.001 0.01 0.1
f(x) 0.99833 0.99998 0.99999 0.99999 0.99998 0.99833
Exercise 9.1 | Q 6 | Page 95

In problems 1 – 6, using the table estimate the value of the limit
`lim_(x -> 0) (cos x - 1)/x`

x – 0.1  – 0.01 – 0.001 0.0001 0.01 0.1
f(x) 0.04995 0.0049999 0.0004999 – 0.0004999 – 0.004999 – 0.04995
Exercise 9.1 | Q 7 | Page 96

In exercise problems 7 – 15, use the graph to find the limits (if it exists). If the limit does not exist, explain why?

`lim_(x -> 3) (4 - x)`

Exercise 9.1 | Q 8 | Page 96

In exercise problems 7 – 15, use the graph to find the limits (if it exists). If the limit does not exist, explain why?

`lim_(x -> 1) (x^2 + 2)`

Exercise 9.1 | Q 9 | Page 96

In exercise problems 7 – 15, use the graph to find the limits (if it exists). If the limit does not exist, explain why?

`lim_(x -> 2) f(x)` where `f(x) = {{:(4 - x",", x ≠ 2),(0",", x = 2):}`

Exercise 9.1 | Q 10 | Page 96

In exercise problems 7 – 15, use the graph to find the limits (if it exists). If the limit does not exist, explain why?

`lim_(x -> 1) f(x)` where `f(x) = {{:(x^2 + 2",", x ≠ 1),(1",", x = 1):}`

Exercise 9.1 | Q 11 | Page 96

In exercise problems 7 – 15, use the graph to find the limits (if it exists). If the limit does not exist, explain why?

`lim_(x -> 3) 1/(x - 3)`

Exercise 9.1 | Q 12 | Page 96

In exercise problems 7 – 15, use the graph to find the limits (if it exists). If the limit does not exist, explain why?

`lim_(x -> 5) |x - 5|/(x - 5)`

Exercise 9.1 | Q 13 | Page 97

In exercise problems 7 – 15, use the graph to find the limits (if it exists). If the limit does not exist, explain why?

`lim_(x -> 1) sin pi x`

Exercise 9.1 | Q 14 | Page 97

In exercise problems 7 – 15, use the graph to find the limits (if it exists). If the limit does not exist, explain why?

`lim_(x -> 0) sec x`

Exercise 9.1 | Q 15 | Page 97

In exercise problems 7 – 15, use the graph to find the limits (if it exists). If the limit does not exist, explain why?

`lim_(x -> x/2) tan x`

Exercise 9.1 | Q 16 | Page 97

Sketch the graph of f, then identify the values of x0 for which `lim_(x -> x_0)` f(x) exists.

f(x) = `{{:(x^2",", x ≤ 2),(8 - 2x",", 2 < x < 4),(4",", x ≥ 4):}`

Exercise 9.1 | Q 17 | Page 97

Sketch the graph of f, then identify the values of x0 for which `lim_(x -> x_0)` f(x) exists.

f(x) = `{{:(sin x",", x < 0),(1 - cos x",", 0 ≤ x ≤ pi),(cos x",", x > pi):}`

Exercise 9.1 | Q 18. (i) | Page 97

Sketch the graph of a function f that satisfies the given value:

f(0) is undefined

`lim_(x -> 0) f(x)` = 4

f(2) = 6

`lim_(x -> 2) f(x)` = 3

Exercise 9.1 | Q 18. (ii) | Page 97

Sketch the graph of a function f that satisfies the given value:

f(– 2) = 0

f(2) = 0

`lim_(x -> 2) f(x)` = 0

`lim_(x -> 2) f(x)` does not exist.

Exercise 9.1 | Q 19 | Page 98

Write a brief description of the meaning of the notation `lim_(x -> 8) f(x)` = 25

Exercise 9.1 | Q 20 | Page 98

If f(2) = 4, can you conclude anything about the limit of f(x) as x approaches 2?

Exercise 9.1 | Q 21 | Page 98

If the limit of f(x) as x approaches 2 is 4, can you conclude anything about f(2)? Explain reasoning

Exercise 9.1 | Q 22 | Page 98

Evaluate : `lim_(x -> 3) (x^2 - 9)/(x - 3)` if it exists by finding `f(3^-)` and `f(3^+)`

Exercise 9.1 | Q 23 | Page 98

Verify the existence of `lim_(x -> 1) f(x)`, where `f(x) = {{:((|x - 1|)/(x - 1)",",  "for"  x ≠ 1),(0",",  "for"  x = 1):}`

Exercise 9.2 [Pages 102 - 103]

Samacheer Kalvi solutions for Mathematics - Volume 1 and 2 [English] Class 11 TN Board 9 Differential Calculus - Limits and Continuity Exercise 9.2 [Pages 102 - 103]

Exercise 9.2 | Q 1 | Page 102

Evaluate the following limits:

`lim_(x -> 2) (x^4 - 16)/(x - 2)`

Exercise 9.2 | Q 2 | Page 102

Evaluate the following limits:

`lim_(x ->) (x^"m" - 1)/(x^"n" - 1)`, m and n are integers

Exercise 9.2 | Q 3 | Page 102

Evaluate the following limits:

`lim_(sqrt(x) -> 3) (x^2 - 81)/(sqrt(x) - 3)`

Exercise 9.2 | Q 4 | Page 102

Evaluate the following limits:

`lim_("h" -> 0) (sqrt(x + "h") - sqrt(x))/"h", x > 0`

Exercise 9.2 | Q 5 | Page 102

Evaluate the following limits:

`lim_(x -> 5) (sqrt(x + 4) - 3)/(x - 5)`

Exercise 9.2 | Q 6 | Page 103

Evaluate the following limits:

`lim_(x -> 2) (1/x - 1/2)/(x - 2)`

Exercise 9.2 | Q 7 | Page 103

Evaluate the following limits:

`lim_(x -> 1) (sqrt(x) - x^2)/(1 - sqrt(x))`

Exercise 9.2 | Q 8 | Page 103

Evaluate the following limits:

`lim_(x -> 0) (sqrt(x^2 + 1) - 1)/(sqrt(x^2 + 16) - 4)`

Exercise 9.2 | Q 9 | Page 103

Evaluate the following limits:

`lim_(x -> 0) (sqrt(1 + x) - 1)/x`

Exercise 9.2 | Q 10 | Page 103

Evaluate the following limits:

`lim_(x -> 1) (root(3)(7 + x^3) - sqrt(3 + x^2))/(x - 1)`

Exercise 9.2 | Q 11 | Page 103

Evaluate the following limits:

`lim_(x -> 2) (2 - sqrt(x + 2))/(root(3)(2) - root(3)(4 - x))`

Exercise 9.2 | Q 12 | Page 103

Evaluate the following limits:

`lim_(x - 0) (sqrt(1 + x^2) - 1)/x`

Exercise 9.2 | Q 13 | Page 103

Evaluate the following limits:

`lim_(x -> 0) (sqrt(1 - x) - 1)/x^2`

Exercise 9.2 | Q 14 | Page 103

Evaluate the following limits:

`lim_(x -> 5) (sqrt(x - 1) - 2)/(x - 5)`

Exercise 9.2 | Q 15 | Page 103

Evaluate the following limits:

`lim_(x -> "a") (sqrt(x - "b") - sqrt("a" - "b"))/(x^2 - "a"^2) ("a" > "b")`

Exercise 9.3 [Page 111]

Samacheer Kalvi solutions for Mathematics - Volume 1 and 2 [English] Class 11 TN Board 9 Differential Calculus - Limits and Continuity Exercise 9.3 [Page 111]

Exercise 9.3 | Q 1. (a) | Page 111

Find the left and right limits of f(x) = `(x^2 - 4)/((x^2 + 4x+ 4)(x + 3))` at x = – 2

Exercise 9.3 | Q 1. (b) | Page 111

Find the left and right limits of f(x) = tan x at x = `pi/2`

Exercise 9.3 | Q 2 | Page 111

Evaluate the following limits:

`lim_(x -> 3) (x^2 - 9)/(x^2(x^2 - 6x + 9))`

Exercise 9.3 | Q 3 | Page 111

Evaluate the following limits:

`lim_(x  -> oo) 3/(x - 2) - (2x + 11)/(x^2 + x - 6)`

Exercise 9.3 | Q 4 | Page 111

Evaluate the following limits:

`lim_(x -> oo) (x^3 + x)/(x^4 - 3x^2 + 1)`

Exercise 9.3 | Q 5 | Page 111

Evaluate the following limits:

`lim_(x -> oo) (x^4 - 5x)/(x^2 - 3x + 1)`

Exercise 9.3 | Q 6 | Page 111

Evaluate the following limits:

`lim_(x -> oo) (1 + x - 3x^3)/(1 + x^2 +3x^3)`

Exercise 9.3 | Q 7 | Page 111

Evaluate the following limits:

`lim_(x ->oo) (x^3/(2x^2 - 1) - x^2/(2x + 1))`

Exercise 9.3 | Q 8. (i) | Page 111

Show that `lim_("n" -> oo) (1 + 2 + 3 + ... + "n")/(3"n"^2 + 7n" + 2) = 1/6`

Exercise 9.3 | Q 8. (ii) | Page 111

Show that  `lim_("n" -> oo) (1^2 + 2^2 + ... + (3"n")^2)/((1 + 2 + ... + 5"n")(2"n" + 3)) = 9/25`

Exercise 9.3 | Q 8. (iii) | Page 111

Show that `lim_("n" -> oo) 1/1.2 + 1/2.3 + 1/3.4 + ... + 1/("n"("n" + 1))` = 1

Exercise 9.3 | Q 9 | Page 111

An important problem in fishery science is to estimate the number of fish presently spawning in streams and use this information to predict the number of mature fish or “recruits” that will return to the rivers during the reproductive period. If S is the number of spawners and R the number of recruits, “Beverton-Holt spawner recruit function” is R(S) = `"S"/((alpha"S" + beta)` where `alpha` and `beta` are positive constants. Show that this function predicts approximately constant recruitment when the number of spawners is sufficiently large

Exercise 9.3 | Q 10 | Page 111

A tank contains 5000 litres of pure water. Brine (very salty water) that contains 30 grams of salt per litre of water is pumped into the tank at a rate of 25 litres per minute. The concentration of salt water after t minutes (in grams per litre) is C(t) = `(30"t")/(200 + "t")`. What happens to the concentration as t → ∞?

Exercise 9.4 [Pages 117 - 118]

Samacheer Kalvi solutions for Mathematics - Volume 1 and 2 [English] Class 11 TN Board 9 Differential Calculus - Limits and Continuity Exercise 9.4 [Pages 117 - 118]

Exercise 9.4 | Q 1 | Page 117

Evaluate the following limits:

`lim_(x -> oo)(1 + 1/x)^(7x)`

Exercise 9.4 | Q 2 | Page 117

Evaluate the following limits:

`lim_(x -> 0)(1 + x)^(1/(3x))`

Exercise 9.4 | Q 3 | Page 117

Evaluate the following limits:

`lim_(x -> oo)(1 + "k"/x)^("m"/x)`

Exercise 9.4 | Q 4 | Page 117

Evaluate the following limits:

`lim_(x -> oo) ((2x^2 + 3)/(2x^2 + 5))^(8x^2 + 3)`

Exercise 9.4 | Q 5 | Page 118

Evaluate the following limits:

`lim_(x -> oo) (1 + 3/x)^(x + 2)`

Exercise 9.4 | Q 6 | Page 118

Evaluate the following limits:

`lim_(x -> 0) (sin^3(x/2))/x^2`

Exercise 9.4 | Q 7 | Page 118

Evaluate the following limits:

`lim_(x -> 0) (sinalphax)/(sinbetax)`

Exercise 9.4 | Q 8 | Page 118

Evaluate the following limits:

`lim_(x -> 0) (tan 2x)/(sin 5x)`

Exercise 9.4 | Q 9 | Page 118

Evaluate the following limits:

`lim_(alpha -> 0) (sin(alpha^"n"))/(sin alpha)^"m"`

Exercise 9.4 | Q 10 | Page 118

Evaluate the following limits:

`lim_(x -> 0) (sin("a" + x) - sin("a" - x))/x`

Exercise 9.4 | Q 11 | Page 118

Evaluate the following limits:

`lim_(x -> 0) (sqrt(x^2 + "a"^2) - "a")/(sqrt(x^2 + "b"^2) - "b")`

Exercise 9.4 | Q 12 | Page 118

Evaluate the following limits:

`lim_(x -> 0) (2 "arc"sinx)/(3x)`

Exercise 9.4 | Q 13 | Page 118

Evaluate the following limits:

`lim_(x-> 0) (1 - cos x)/x^2`

Exercise 9.4 | Q 14 | Page 118

Evaluate the following limits:

`lim_(x -> 0) (tan 2x)/x`

Exercise 9.4 | Q 15 | Page 118

Evaluate the following limits:

`lim_(x -> 0) (2^x - 3^x)/x`

Exercise 9.4 | Q 16 | Page 118

Evaluate the following limits:

`lim_(x -> 0) (3^x - 1)/(sqrt(x + 1) - 1)`

Exercise 9.4 | Q 17 | Page 118

Evaluate the following limits:

`lim_(x -> 0) (1 - cos^2x)/(x sin2x)`

Exercise 9.4 | Q 18 | Page 118

Evaluate the following limits:

`lim_(x -> oo) x [3^(1/x) + 1 - cos(1/x) - "e"^(1/x)]`

Exercise 9.4 | Q 19 | Page 118

Evaluate the following limits:

`lim_(x - oo){x[log(x + "a") - log(x)]}`

Exercise 9.4 | Q 20 | Page 118

Evaluate the following limits:

`lim_(x -> pi) (sin3x)/(sin2x)`

Exercise 9.4 | Q 21 | Page 118

Evaluate the following limits:

`lim_(x -> pi) (1 + sinx)^(2"cosec"x)`

Exercise 9.4 | Q 22 | Page 118

Evaluate the following limits:

`lim_(x -> 0) (sqrt(2) - sqrt(1 + cosx))/(sin^2x)`

Exercise 9.4 | Q 23 | Page 118

Evaluate the following limits:

`lim_(x -> 0) (sqrt(1 + sinx) - sqrt(1 - sinx))/tanx`

Exercise 9.4 | Q 24 | Page 118

Evaluate the following limits:

`lim_(x -> oo) ((x^2 - 2x + 1)/(x^2 -4x + 2))^x`

Exercise 9.4 | Q 25 | Page 118

Evaluate the following limits:

`lim_(x -> 0) ("e"^x - "e"^(-x))/sinx`

Exercise 9.4 | Q 26 | Page 118

Evaluate the following limits:

`lim_(x -> 0) ("e"^("a"x) - "e"^("b"x))/x`

Exercise 9.4 | Q 27 | Page 118

Evaluate the following limits:

`lim_(x -> ) (sinx(1 - cosx))/x^3`

Exercise 9.4 | Q 28 | Page 118

Evaluate the following limits:

`lim_(x -> 0) (tan x - sin x)/x^3`

Exercise 9.5 [Pages 127 - 129]

Samacheer Kalvi solutions for Mathematics - Volume 1 and 2 [English] Class 11 TN Board 9 Differential Calculus - Limits and Continuity Exercise 9.5 [Pages 127 - 129]

Exercise 9.5 | Q 1 | Page 127

Prove that f(x) = 2x2 + 3x - 5 is continuous at all points in R

Exercise 9.5 | Q 2. (i) | Page 127

Examine the continuity of the following:

x + sin x

Exercise 9.5 | Q 2. (ii) | Page 127

Examine the continuity of the following:

x2 cos x

Exercise 9.5 | Q 2. (iii) | Page 127

Examine the continuity of the following:

ex tan x

Exercise 9.5 | Q 2. (iv) | Page 127

Examine the continuity of the following:

e2x + x2

Exercise 9.5 | Q 2. (v) | Page 127

Examine the continuity of the following:

x . log x

Exercise 9.5 | Q 2. (vi) | Page 127

Examine the continuity of the following:

`sinx/x^2`

Exercise 9.5 | Q 2. (vii) | Page 127

Examine the continuity of the following:

`(x^2 - 16)/(x + 4)`

Exercise 9.5 | Q 2. (viii) | Page 127

Examine the continuity of the following:

|x + 2| + |x – 1|

Exercise 9.5 | Q 2. (ix) | Page 127

Examine the continuity of the following:

`|x - 2|/|x + 1|`

Exercise 9.5 | Q 2. (x) | Page 127

Examine the continuity of the following:

cot x + tan x

Exercise 9.5 | Q 3. (i) | Page 127

Find the points of discontinuity of the function f, where `f(x) = {{:(4x + 5",",  "if",  x ≤ 3),(4x - 5",",  "if",  x > 3):}`

Exercise 9.5 | Q 3. (ii) | Page 127

Find the points of discontinuity of the function f, where `f(x) = {{:(x + 2",",  "if",  x ≥ 2),(x^2",",  "if",  x < 2):}`

Exercise 9.5 | Q 3. (iii) | Page 127

Find the points of discontinuity of the function f, where `f(x) = {{:(x^3 - 3",",  "if"  x ≤ 2),(x^2 + 1",",  "if"  x < 2):}`

Exercise 9.5 | Q 3. (iv) | Page 127

Find the points of discontinuity of the function f, where `f(x) = {{:(sinx",",  0 ≤ x ≤ pi/4),(cos x",", pi/4 < x < pi/2):}`

Exercise 9.5 | Q 4. (i) | Page 127

At the given point x0 discover whether the given function is continuous or discontinuous citing the reasons for your answer:

x0 = 1, `f(x) = {{:((x^2 - 1)/(x - 1)",", x ≠ 1),(2",", x = 1):}`

Exercise 9.5 | Q 4. (ii) | Page 127

At the given point x0 discover whether the given function is continuous or discontinuous citing the reasons for your answer:

x0 = 3, `f(x) = {{:((x^2 - 9)/(x - 3)",", "if"  x ≠ 3),(5",", "if"  x = 3):}`

Exercise 9.5 | Q 5 | Page 127

Show that the function `{{:((x^3 - 1)/(x - 1)",",  "if"  x ≠ 1),(3",",  "if"  x = 1):}` is continuous om `(- oo, oo)`

Exercise 9.5 | Q 6 | Page 127

For what value of `alpha` is this function `f(x) = {{:((x^4 - 1)/(x - 1)",",  "if"  x ≠ 1),(alpha",",  "if"  x = 1):}` continuous at x = 1?

Exercise 9.5 | Q 7 | Page 128

Let `f(x) = {{:(0",",  "if"  x < 0),(x^2",",  "if"  0 ≤ x ≤ 2),(4",",  "if"  x ≥ 2):}`. Graph the function. Show that f(x) continuous on `(- oo, oo)`

Exercise 9.5 | Q 8 | Page 128

If f and g are continuous functions with f(3) = 5 and `lim_(x -> 3) [2f(x) - g(x)]` = 4, find g(3)

Exercise 9.5 | Q 9. (i) | Page 128

Find the points at which f is discontinuous. At which of these points f is continuous from the right, from the left, or neither? Sketch the graph of f.

`f(x) = {{:(2x + 1",",  "if"  x ≤ - 1),(3x",",  "if"  - 1 < x < 1),(2x - 1",",  "if"  x ≥ 1):}`

Exercise 9.5 | Q 9. (ii) | Page 128

Find the points at which f is discontinuous. At which of these points f is continuous from the right, from the left, or neither? Sketch the graph of f.

`f(x) = {{:((x - 1)^3",",  "if"  x < 0),((x + 1)^3",",  "if"  x ≥ 0):}`

Exercise 9.5 | Q 10 | Page 128

A function f is defined as follows:

`f(x) = {{:(0,  "for"  x < 0;),(x,  "for"  0 ≤ x ≤ 1;),(- x^2 +4x - 2, "for"  1 ≤ x ≤ 3;),(4 - x,  "for"  x ≥ 3):}`
Is the function continuous?

Exercise 9.5 | Q 11. (i) | Page 128

Which of the following functions f has a removable discontinuity at x = x0? If the discontinuity is removable, find a function g that agrees with f for x ≠ x0 and is continuous on R.

`f(x) = (x^2 - 2x - 8)/(x + 2), x_0` = – 2

Exercise 9.5 | Q 11. (ii) | Page 128

Which of the following functions f has a removable discontinuity at x = x0? If the discontinuity is removable, find a function g that agrees with f for x ≠ x0 and is continuous on R.

`f(x) = (x^3 + 64)/(x + 4), x_0` = – 4

Exercise 9.5 | Q 11. (iii) | Page 128

Which of the following functions f has a removable discontinuity at x = x0? If the discontinuity is removable, find a function g that agrees with f for x ≠ x0 and is continuous on R.

`f(x) = (3 - sqrt(x))/(9 - x), x_0` = 9

Exercise 9.5 | Q 12 | Page 128

Find the constant b that makes g continuous on `(- oo, oo)`.

`g(x) = {{:(x^2 - "b"^2,"if"  x < 4),("b"x + 20,  "if"  x ≥ 4):}`

Exercise 9.5 | Q 13 | Page 128

Consider the function  `f(x) = x sin  pi/x`. What value must we give f(0) in order to make the function continuous everywhere?

Exercise 9.5 | Q 14 | Page 128

The function `f(x) = (x^2 - 1)/(x^3 - 1)` is not defined at x = 1. What value must we give f(1) inorder to make f(x) continuous at x =1?

Exercise 9.5 | Q 15. (a) | Page 129

State how continuity is destroyed at x = x0 for the following graphs.

Exercise 9.5 | Q 15. (b) | Page 129

State how continuity is destroyed at x = x0 for the following graphs.

Exercise 9.5 | Q 15. (c) | Page 129

State how continuity is destroyed at x = x0 for the following graphs.

Exercise 9.5 | Q 15. (d) | Page 129

State how continuity is destroyed at x = x0 for the following graphs.

Exercise 9.6 [Pages 129 - 131]

Samacheer Kalvi solutions for Mathematics - Volume 1 and 2 [English] Class 11 TN Board 9 Differential Calculus - Limits and Continuity Exercise 9.6 [Pages 129 - 131]

Exercise 9.6 | Q 1 | Page 129

Choose the correct alternative:

`lim_(x -> oo) sinx/x`

  • 1

  • 0

  • `oo`

  • `- oo`

Exercise 9.6 | Q 2 | Page 129

Choose the correct alternative:

`lim_(x - pi/2) (2x - pi)/cos x`

  • 2

  • 1

  • −2

  • 0

Exercise 9.6 | Q 3 | Page 129

Choose the correct alternative:

`lim_(x -> 0) sqrt(1 - cos 2x)/x`

  • 0

  • 1

  • `sqrt(2)`

  • does not exist

Exercise 9.6 | Q 4 | Page 129

Choose the correct alternative:

`lim_(theta -> 0) (sinsqrt(theta))/(sqrt(sin theta)`

  • 1

  • – 1

  • 0

  • 2

Exercise 9.6 | Q 5 | Page 129

Choose the correct alternative:

`lim_(x -> oo) ((x^2 + 5x + 3)/(x^2 + x + 3))^x` is

  • e4

  • e2

  • e3

  • 1

Exercise 9.6 | Q 6 | Page 130

Choose the correct alternative:

`lim_(x - oo) sqrt(x^2 - 1)/(2x + 1)` =

  • 1

  • 0

  • – 1

  • `1/2`

Exercise 9.6 | Q 7 | Page 130

Choose the correct alternative:

`lim_(x -> 0) ("a"^x - "b"^x)/x` =

  • log ab

  • `log ("a"/"b")`

  • `log ("b"/"a")`

  • `"a"/"b"`

Exercise 9.6 | Q 8 | Page 130

Choose the correct alternative:

`lim_(x -> 0) (8^x - 4x - 2^x + 1^x)/x^2` =

  • 2 log 2

  • 2(log)2 

  • log 2

  • 3 log 2

Exercise 9.6 | Q 9 | Page 130

Choose the correct alternative:

If `f(x) = x(- 1)^([1/x])`, x ≤ 0, then the value of `lim_(x -> 0) f(x)` is equal to

  • – 1

  • 0

  • 2

  • 4

Exercise 9.6 | Q 10 | Page 130

Choose the correct alternative:

`lim_(x -> 3) [x]` =

  • 2

  • 3

  • does not exist

  • 0

Exercise 9.6 | Q 11 | Page 130

Choose the correct alternative:

Let the function f be defined by `f(x) = {{:(3x, 0 ≤ x ≤ 1),(-3 + 5, 1 < x ≤ 2):}`, then

  • `lim_(x -> 1) f(x)` = 1

  • `lim_(x -> 1) f(x)` = 3

  • `lim_(x -> 1) f(x)` = 2

  • `lim_(x -> 1) f(x)` does not exist

Exercise 9.6 | Q 12 | Page 130

Choose the correct alternative:

If f : R → R is defined by `f(x) = [x - 3] + |x - 4|` for x ∈ R then `lim_(x -> 3^-) f(x)` is equal to

  • – 2

  • – 1

  • 0

  • 1

Exercise 9.6 | Q 13 | Page 130

Choose the correct alternative:

`lim_(x -> 0) (x"e"^x - sin x)/x` is

  • 1

  • 2

  • 3

  • 0

Exercise 9.6 | Q 14 | Page 130

Choose the correct alternative:

If `lim_(x -> 0) (sin "p"x)/(tan 3x)` = 4, then the value of p is

  • 6

  • 9

  • 12

  • 4

Exercise 9.6 | Q 15 | Page 130

Choose the correct alternative:

`lim_(alpha - pi/4) (sin alpha - cos alpha)/(alpha - pi/4)` is

  • `sqrt(2)`

  • `1/sqrt(2)`

  • 1

  • 2

Exercise 9.6 | Q 16 | Page 130

Choose the correct alternative:

`lim_(x -> oo) (1/"n"^2 + 2/"n"^2 + 3/"n"^2 + ... + "n"/"n"^2)` is

  • `1/2`

  • 0

  • 1

  • `oo`

Exercise 9.6 | Q 17 | Page 131

Choose the correct alternative:

`lim_(x -> 0) ("e"^(sin x) - 1)/x` =

  • 1

  • e

  • `1/"e"`

  • 0

Exercise 9.6 | Q 18 | Page 131

Choose the correct alternative:

`lim_(x -> 0) ("e"^tanx - "e"^x)/(tan x - x)` =

  • 1

  • e

  • `1/2`

  • 0

Exercise 9.6 | Q 19 | Page 131

Choose the correct alternative:

The value of `lim_(x -> 0) sinx/sqrt(x^2)` is

  • 1

  • – 1

  • 0

  • limit does not exist

Exercise 9.6 | Q 20 | Page 131

Choose the correct alternative:

The value of `lim_(x -> "k") x - [x]`, where k is an integer is

  • – 1

  • 1

  • 0

  • 2

Exercise 9.6 | Q 21 | Page 131

Choose the correct alternative:

At x = `3/2` the function f(x) = `|2x - 3|/(2x - 3)` is

  • Continuous

  • Discontinuous

  • Differentiable

  • Non-zero

Exercise 9.6 | Q 22 | Page 131

Choose the correct alternative:

Let f : R → R be defined by `f(x) = {{:(x, x  "is irrational"),(1 - x, x  "is rational"):}` then f is

  • Discontinuous at x = `1/2`

  • Continuous at x = `1/2`

  • Continuous everywhere

  • Discontinuous everywhere

Exercise 9.6 | Q 23 | Page 131

Choose the correct alternative:

The function `f(x) = {{:((x^2 - 1)/(x^3 + 1), x ≠ - 1),("P", x = -1):}` is not defined for x = −1. The value of f(−1) so that the function extended by this value is continuous is

  • `2/3`

  • `- 2/3`

  • 1

  • 0

Exercise 9.6 | Q 24 | Page 131

Choose the correct alternative:

Let f be a continuous function on [2, 5]. If f takes only rational values for all x and f(3) = 12, then f(4.5) is equal to

  • `(f(3) + f(4.5))/7.5`

  • 12

  • 17.5

  • `(f(4.5) - f(3))/1.5`

Exercise 9.6 | Q 25 | Page 131

Choose the correct alternative:

Let a function f be defined by `f(x) = (x - |x|)/x` for x ≠ 0 and f(0) = 2. Then f is

  • Continuous nowhere

  • Continuous everywhere

  • Continuous for all x except x = 1

  • Continuous for all x except x = 0

Solutions for 9: Differential Calculus - Limits and Continuity

Exercise 9.1Exercise 9.2Exercise 9.3Exercise 9.4Exercise 9.5Exercise 9.6
Samacheer Kalvi solutions for Mathematics - Volume 1 and 2 [English] Class 11 TN Board chapter 9 - Differential Calculus - Limits and Continuity - Shaalaa.com

Samacheer Kalvi solutions for Mathematics - Volume 1 and 2 [English] Class 11 TN Board chapter 9 - Differential Calculus - Limits and Continuity

Shaalaa.com has the Tamil Nadu Board of Secondary Education Mathematics Mathematics - Volume 1 and 2 [English] Class 11 TN Board Tamil Nadu Board of Secondary Education solutions in a manner that help students grasp basic concepts better and faster. The detailed, step-by-step solutions will help you understand the concepts better and clarify any confusion. Samacheer Kalvi solutions for Mathematics Mathematics - Volume 1 and 2 [English] Class 11 TN Board Tamil Nadu Board of Secondary Education 9 (Differential Calculus - Limits and Continuity) include all questions with answers and detailed explanations. This will clear students' doubts about questions and improve their application skills while preparing for board exams.

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Concepts covered in Mathematics - Volume 1 and 2 [English] Class 11 TN Board chapter 9 Differential Calculus - Limits and Continuity are Introduction to Differential Calculus -limits and Continuity, Continuity, Concept of Limits.

Using Samacheer Kalvi Mathematics - Volume 1 and 2 [English] Class 11 TN Board solutions Differential Calculus - Limits and Continuity exercise by students is an easy way to prepare for the exams, as they involve solutions arranged chapter-wise and also page-wise. The questions involved in Samacheer Kalvi Solutions are essential questions that can be asked in the final exam. Maximum Tamil Nadu Board of Secondary Education Mathematics - Volume 1 and 2 [English] Class 11 TN Board students prefer Samacheer Kalvi Textbook Solutions to score more in exams.

Get the free view of Chapter 9, Differential Calculus - Limits and Continuity Mathematics - Volume 1 and 2 [English] Class 11 TN Board additional questions for Mathematics Mathematics - Volume 1 and 2 [English] Class 11 TN Board Tamil Nadu Board of Secondary Education, and you can use Shaalaa.com to keep it handy for your exam preparation.

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