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![Balbharati solutions for Mathematics and Statistics 1 (Arts and Science) [English] 11 Standard Maharashtra State Board chapter 3 - Trigonometry - 2 Balbharati solutions for Mathematics and Statistics 1 (Arts and Science) [English] 11 Standard Maharashtra State Board chapter 3 - Trigonometry - 2 - Shaalaa.com](/images/mathematics-and-statistics-1-arts-and-science-english-11-standard-maharashtra-state-board_6:e3c01670e36a48e499844fcbaf828475.jpg)
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Solutions for Chapter 3: Trigonometry - 2
Below listed, you can find solutions for Chapter 3 of Maharashtra State Board Balbharati for Mathematics and Statistics 1 (Arts and Science) [English] 11 Standard Maharashtra State Board.
Balbharati solutions for Mathematics and Statistics 1 (Arts and Science) [English] 11 Standard Maharashtra State Board 3 Trigonometry - 2 Exercise 3.1 [Pages 39 - 40]
Find the value of:
sin 15°
Find the values of:
cos 75°
Find the values of:
tan 105°
Find the values of:
cot 225°
Prove the following:
`cos (pi/2 - x) cos(pi/2 - y) - sin(pi/2 - x) sin(pi/2 - y)` = – cos (x + y)
Prove the following:
`tan(pi/4 + theta) = (1 + tan theta)/(1 - tan theta)`
Prove the following:
`((1 + tan x)/(1 - tan x))^2 = tan(pi/4 + x)/(tan(pi/4 - x))`
Prove the following:
sin [(n + 1)A]. sin [(n + 2)A] + cos [(n + 1)A]. cos [(n + 2)A] = cos A
Prove the following:
`sqrt(2)cos (pi/4 - "A")` = cos A + sin A
Prove the following:
`(cos(x - y))/(cos(x + y)) = (cotx coty + 1)/(cotx coty - 1)`
Prove the following:
cos(x + y).cos(x − y) = cos2y − sin2x
Prove the following:
`(tan5"A" - tan3"A")/(tan5"A" + tan3"A") = (sin2"A")/(sin8"A")`
Prove the following:
tan8θ − tan5θ − tan3θ = tan8θ · tan5θ · tan3θ
Prove the following:
tan50° = tan40° + 2 tan10°
Prove the following:
`(cos27^circ + sin27^circ)/(cos27^circ - sin27^circ)` = tan72°
Prove the following:
tan10° + tan35° + tan10°.tan35° = 1
Prove the following:
`(cot"A"cot4"A" + 1)/(cot"A" cot4"A" - 1) = (cos3"A")/(cos5"A")`
Prove the following:
`(cos15^circ - sin15^circ)/(cos15^circ + sin15^circ) = 1/sqrt(3)`
If sin A = `(-5)/13, pi < "A" < (3pi)/2` and cos B = `3/5, (3pi)/2 < "B" < 2pi` find sin (A + B)
If sin A = `(-5)/13, pi < "A" < (3pi)/2` and cos B = `3/5, (3pi)/2 < "B" < 2pi` find cos (A – B)
If sin A = `(-5)/13, pi < "A" < (3pi)/2` and cos B = `3/5, (3pi)/2 < "B" < 2pi` find tan (A + B)
If tan A = `5/6, tan "B" = 1/11`, prove that A + B = `pi/4`
Balbharati solutions for Mathematics and Statistics 1 (Arts and Science) [English] 11 Standard Maharashtra State Board 3 Trigonometry - 2 Exercise 3.2 [Page 42]
Find the value of :
sin 690°
Find the value of :
sin (495°)
Find the value of :
cos 315°
Find the value of :
cos (600°)
Find the value of :
tan 225°
Find the value of :
tan (– 690°)
Find the value of :
sec 240°
Find the value of :
sec (– 855°)
Find the value of :
cosec 780°
Find the value of :
cot (– 1110°)
Prove the following:
`(cos(pi + x) cos(-x))/(sin(pi - x)cos(pi/2 + x))` = cot2x
Prove the following:
`cos((3pi)/2 + x) cos(2pi + x)[cot((3pi)/2 - x) + cot(2pi + x)]` = 1
Prove the following:
sec 840° . cot (– 945°) + sin 600° tan (– 690°) = `3/2`
Prove the following:
`("cosec"(90^circ - x)sin(180^circ - x)cot(360^circ - x))/(sec(180^circ + x)tan(90^circ + x)sin(-x))` = 1
Prove the following:
`(sin^3(pi + x)sec^2(pi - x)tan(2pi - x))/(cos^2(pi/2 + x)sin(pi - x)"cosec"^2 - x)` = tan3x
Prove the following:
cosθ + sin (270° + θ) − sin (270° − θ) + cos (180° + θ) = 0
Balbharati solutions for Mathematics and Statistics 1 (Arts and Science) [English] 11 Standard Maharashtra State Board 3 Trigonometry - 2 Exercise 3.3 [Page 48]
Find the value of :
`sin pi/8`
Find the value of :
`cos pi/8`
Find sin 2x, cos 2x, tan 2x if secx = `(-13)/5, pi/2 < x < pi`
Prove the following:
`(1 - cos2theta)/(1 + cos2theta)` = tan2θ
Prove the following:
(sin 3x + sin x)sin x + (cos 3x – cos x) cos x = 0
Prove the following:
(cos x + cos y)2 + (sin x – sin y)2 = `4cos^2 ((x + y))/2`
Prove the following:
(cos x – cos y)2 + (sin x – sin y)2 = `4sin^2 ((x - y))/2`
Prove the following:
tan x + cot x = 2 cosec 2x
Prove the following:
`(cosx + sinx)/(cosx - sinx) - (cosx - sinx)/(cosx + sinx)` = 2tan2x
Prove the following:
`sqrt(2 + sqrt(2 + sqrt(2 + 2cos8x)` = 2 cos x
Prove the following:
16 sin θ cos θ cos 2θ cos 4θ cos 8θ = sin 16θ
Prove the following:
`(sin3x)/cosx + (cos3x)/sinx` = 2 cot 2x
Prove the following:
`cosx/(1 + sinx) = (cot(x/2) - 1)/(cot(x/2) + 1)`
Prove the following:
`(tan(theta/2) + cot(theta/2))/(cot(theta/2) - tan(theta/2))` = secθ
Prove the following:
`1/(tan3"A" - tan"A") - 1/(cot3"A" - cot"A")` = cot2A
Prove the following:
cos7° cos 14° cos28° cos 56° = `sin68^circ/(16cos83^circ)`
Prove the following:
`(sin^2(-160^circ))/(sin^(2)70^circ) + sin(180^circ - theta)/sintheta` = sec220°
Prove the following:
`(2cos 4x + 1)/(2cosx + 1)` = (2 cos x – 1) (2 cos 2x – 1)
Prove the following:
cos2x + cos2(x + 120°) + cos2(x – 120°) = `3/2`
Prove the following:
2cosec 2x + cosec x = `secx cot(x/2)`
Prove the following:
`4 cos x. cos(x + pi/3) . cos (x - pi/3)` = cos 3x
Prove the following:
`sinx tan(x/2) + 2cosx = 2/(1 + tan^2(x/2))`
Balbharati solutions for Mathematics and Statistics 1 (Arts and Science) [English] 11 Standard Maharashtra State Board 3 Trigonometry - 2 Exercise 3.4 [Page 51]
Express the following as a sum or difference of two trigonometric function:
2 sin 4x cos 2x
Express the following as a sum or difference of two trigonometric function:
`2sin (2pi)/3 cos pi/2`
Express the following as a sum or difference of two trigonometric function:
2 cos 4θ cos 2θ
Express the following as a sum or difference of two trigonometric function:
2 cos 35° cos 75°
Prove the following :
`(sin2x + sin2y)/(sin2x - sin2y) = (tan(x + y))/(tan(x - y))`
Prove the following :
sin 6x + sin 4x – sin 2x = 4 cos x sin 2x cos 3x
Prove the following :
`(sinx - sin3x + sin5x - sin7x)/(cosx - cos3x - cos5x + cos7x)` = cot2x
Prove the following :
sin 18° cos 39° + sin 6° cos 15° = sin 24° cos 33°
Prove the following :
cos 20° cos 40° cos 60° cos 80° = `1/16`
Prove the following :
sin 20° sin 40° sin 60° sin 80° = `3/16`
Balbharati solutions for Mathematics and Statistics 1 (Arts and Science) [English] 11 Standard Maharashtra State Board 3 Trigonometry - 2 Exercise 3.5 [Page 54]
In ΔABC, A + B + C = π show that
cos 2A + cos 2B + cos 2C = –1 – 4 cos A cos B cos C
In ΔABC, A + B + C = π show that
sin A + sin B + sin C = `4cos "A"/2 cos "B"/2 cos "C"/2 `
In ΔABC, A + B + C = π show that
cos A + cos B – cos C = `4cos "A"/2 cos "B"/2 sin "C"/2 - 1`
In ΔABC, A + B + C = π show that
sin2A + sin2B − sin2C = 2 sin A sin B cos C
In ΔABC, A + B + C = π show that
`sin^2 "A"/2 + sin^2 "B"/2 - sin^2 "C"/2 = 1 - 2cos "A"/2 cos "B"/2 sin "C"/2`
In ΔABC, A + B + C = π show that
`cot "A"/2 + cot "B"/2 + cot "C"/2 = cot "A"/2 cot "B"/2 cot "C"/2`
In ΔABC, A + B + C = π show that
tan 2A + tan 2B + tan 2C = tan 2A tan 2B tan 2C
In ΔABC, A + B + C = π show that
cos2A +cos2B – cos2C = 1 – 2 sin A sin B cos C
Balbharati solutions for Mathematics and Statistics 1 (Arts and Science) [English] 11 Standard Maharashtra State Board 3 Trigonometry - 2 Miscellaneous Exercise 3 [Pages 56 - 58]
Select the correct option from the given alternatives :
The value of sin(n + 1) A sin (n + 2) A + cos(n + 1) A cos(n + 2) A is equal to
sin A
cos A
– cos A
sin 2A
Select the correct option from the given alternatives :
If tan A – tan B = x and cot B – cot A = y, then cot (A – B) = _____
`1/y - 1/x`
`1/x - 1/y`
`1/x + 1/y`
`(xy)/(x - y)`
Select the correct option from the given alternatives :
If sin θ = n sin (θ + 2α), then tan (θ + α) is equal to
`(1 + n)/(2 - n) tan alpha`
`(1 - n)/(1 + n) tan alpha`
tan α
`(1 + n)/(1 - n) tan alpha`
Select the correct option from the given alternatives:
The value of `costheta/(1 + sin theta)` is equal to .....
`tan(theta/2 - pi/4)`
`tan(-pi/4 - theta/2)`
`tan(pi/4 - theta/2)`
`tan(pi/4 + theta/2)`
Select the correct option from the given alternatives :
The value of cos A cos (60° – A) cos (60° + A) is equal to ......
`1/2cos3"A"`
cos 3A
`1/4cos3"A"`
4 cos 3A
Select the correct option from the given alternatives :
The value of `sin pi/14sin (3pi)/14sin (5pi)/14sin (7pi)/14sin (9pi)/14sin (11pi)/14sin (13pi)/14` is ....
`1/16`
`1/64`
`1/128`
`1/256`
Select the correct option from the given alternatives :
If α + β + γ = π then the value of sin2α + sin2β – sin2γ is equal to …......
2 sin α
2 sin α cos β sin γ
2 sin α sin β cos γ
2 sin α sin β sin γ
Select the correct option from the given alternatives :
Let 0 < A, B < `pi/2` satisfying the equation 3 sin2A + 2 sin2B = 1 and 3 sin 2A − 2 sin 2B = 0 then A + 2B is equal to ______
π
`pi/2`
`pi/4`
2π
Select the correct option from the given alternatives :
In ∆ABC if cot A cot B cot C > 0 then the triangle is _________
Acute angled
right angled
obtuse angled
isosceles right angled
Select the correct option from the given alternatives :
The numerical value of tan 20° tan 80° cot 50° is equal to ______.
`sqrt(3)`
`1/sqrt(3)`
`2sqrt(3)`
`1/(2sqrt(3)`
Prove the following:
tan 20° tan 80° cot 50° = `sqrt(3)`
Prove the following:
If sin α sin β − cos α cos β + 1 = 0 then prove cot α tan β = −1
Prove the following:
`cos (2pi)/15 cos (4pi)/15cos (8pi)/15cos (16pi)/15 = 1/16`
Prove the following:
`(1 + cos pi/8)(1 + cos (3pi)/8)(1 + cos (5pi)/8)(1 + cos (7pi)/8) = 1/8`
Prove the following:
cos 12°+ cos 84° + cos 156° + cos 132° = `-1/2`
Prove the following:
`cos(pi/4 + x) + cos(pi/4 - x) = sqrt(2)cosx`
Prove the following:
`(sin5x - 2sin3x + sinx)/(cos5x - cosx)` = tanx
Prove the following:
sin26x − sin24x = sin2x sin10x
Prove the following:
cos22x − cos26x = sin4x sin8x
Prove the following:
cot4x (sin5x + sin3x) = cotx (sin5x − sin3x)
Prove the following:
`(cos9x - cos5x)/(sin17x - sin3x) = - (sin2x)/(cos10x)`
Prove the following:
If sin 2A = λsin 2B then prove that `(tan("A" + "B"))/(tan("A" - "B")) = (lambda + 1)/(lambda - 1)`
Prove the following:
`(2cos2"A" + 1)/(2cos2"A" - 1)` = tan(60° + A) tan(60° − A)
Prove the following:
tanA + tan(60° + A) + tan(120° + A) = 3 tan 3A
Prove the following:
3tan610° – 27 tan410° + 33tan210° = 1
Prove the following:
cosec 48° + cosec 96° + cosec 192° + cosec 384° = 0
Prove the following:
3(sin x – cos x)4 + 6(sin x + cos x)2 + 4(sin6x + cos6x) = 13
Prove the following:
tan A + 2 tan 2A + 4 tan 4A + 8 cot 8A = cot A
Prove the following:
If A + B + C = `(3pi)/2`, then cos 2A + cos 2B + cos 2C = 1 − 4 sin A sin B sin C
Prove the following:
In any triangle ABC, sin A − cos B = cos C then ∠B = `pi/2`.
Prove the following:
`tan^3x/(1 + tan^2x) + cot^3x/(1 + cot^2x)` = secx cosecx − 2sinx cosx
Prove the following:
sin 20° sin 40° sin 80° = `sqrt(3)/8`
Prove the following:
sin 18° = `(sqrt(5) - 1)/4`
Prove the following:
cos 36° = `(sqrt(5) + 1)/4`
Prove the following:
sin 36° = `(sqrt(10 - 2sqrt(5)))/4`
Prove the following:
`sin pi^"c"/8 = 1/2sqrt(2 - sqrt(2))`
Prove the following:
`tan pi/8 = sqrt(2) - 1`
Prove the following:
tan6° tan42° tan66° tan78° = 1
Prove the following:
sin47° + sin61° − sin11° − sin25° = cos7°
Prove the following:
`sqrt(3) "cosec"20^circ - sec20^circ` = 4
Prove the following:
In ∆ABC, ∠C = `(2pi)/3`, then prove that cos2A + cos2B − cos A cos B = `3/4`
Solutions for 3: Trigonometry - 2
![Balbharati solutions for Mathematics and Statistics 1 (Arts and Science) [English] 11 Standard Maharashtra State Board chapter 3 - Trigonometry - 2 Balbharati solutions for Mathematics and Statistics 1 (Arts and Science) [English] 11 Standard Maharashtra State Board chapter 3 - Trigonometry - 2 - Shaalaa.com](/images/mathematics-and-statistics-1-arts-and-science-english-11-standard-maharashtra-state-board_6:e3c01670e36a48e499844fcbaf828475.jpg)
Balbharati solutions for Mathematics and Statistics 1 (Arts and Science) [English] 11 Standard Maharashtra State Board chapter 3 - Trigonometry - 2
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Concepts covered in Mathematics and Statistics 1 (Arts and Science) [English] 11 Standard Maharashtra State Board chapter 3 Trigonometry - 2 are Trigonometric Functions of Sum and Difference of Angles, Trigonometric Functions of Allied Angels, Trigonometric Functions of Multiple Angles, Trigonometric Functions of Double Angles, Trigonometric Functions of Triple Angle, Factorization Formulae, Formulae for Conversion of Sum Or Difference into Product, Formulae for Conversion of Product in to Sum Or Difference, Trigonometric Functions of Angles of a Triangle.
Using Balbharati Mathematics and Statistics 1 (Arts and Science) [English] 11 Standard Maharashtra State Board solutions Trigonometry - 2 exercise by students is an easy way to prepare for the exams, as they involve solutions arranged chapter-wise and also page-wise. The questions involved in Balbharati Solutions are essential questions that can be asked in the final exam. Maximum Maharashtra State Board Mathematics and Statistics 1 (Arts and Science) [English] 11 Standard Maharashtra State Board students prefer Balbharati Textbook Solutions to score more in exams.
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